X^2+4x-1020=0

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Solution for X^2+4x-1020=0 equation: 



X^2+4X-1020=0

a = 1; b = 4; c = -1020;
Δ = b2-4ac
Δ = 42-4·1·(-1020)
Δ = 4096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4096}=64$


$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-64}{2*1}=\frac{-68}{2}
=-34
$


$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+64}{2*1}=\frac{60}{2}
=30
$

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